0=12x^2-500X

Solution for 0=12x^2-500X equation:

0=12x^2-500x

We move all terms to the left:

0-(12x^2-500x)=0

We add all the numbers together, and all the variables

-(12x^2-500x)=0

We get rid of parentheses

-12x^2+500x=0

a = -12; b = 500; c = 0;
Δ = b2-4ac
Δ = 5002-4·(-12)·0
Δ = 250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{250000}=500$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(500)-500}{2*-12}=\frac{-1000}{-24}
=41+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(500)+500}{2*-12}=\frac{0}{-24}
=0
$